At 25^{\circ} {\C}, the enthalpy of the following processes are given: {\H}_2( {\g})+ {\O}_2( {\g}) \to 2 {\OH}( {\g}) ∆ {\H}^0=78 {\kJ} {\mol}^{-1} {\H}_2( {\g})+1 \/ 2 {\O}_2( {\g}) \to {\H}_2 {\O}( {\g}) ∆ {\H}^0=-242 {\kJ} {\mol}^{-1} {\H}_2( {\g}) \to 2 {\H}( {\g}) ∆ {\H}^0=436 {\kJ} {\mol}^{-1} 1 \/ 2 {\O}_2( {\g}) \to {\O}( {\g}) ∆ {\H}^0=249 {\kJ} {\mol}^{-1} What would be the value of {\X} for the following reaction? _______ (Nearest integer) {\H}_2 {\O}( {\g}) \to {\H}( {\g})+ {\OH}( {\g}) ∆ {\H}^{ {\o}}= {\X} {\kJ} {\mol}^{-1} [1-Feb-2023 Shift 1]

JEE Mains 1-Feb-2023 Shift 1 Solved Paper

Section: Chemistry

Question : 59 of 90

Marks: +1, -0

At 25∘C, the enthalpy of the following processes are given:
‌H2(g)+O2(g)→2‌OH(g)∆H0=78‌kJ‌mol−1
‌H2(g)+1∕2O2(g)→H2O(g)∆H0=−242‌kJ‌mol−1
‌H2(g)→2H(g)∆H0=436‌kJ‌mol−1
‌1∕2O2(g)→O(g)∆H0=249‌kJ‌mol−1
What would be the value of X for the following reaction? _______ (Nearest integer)
H2O(g)→H(g)+OH(g)∆Ho=X‌kJ‌mol−1

[1-Feb-2023 Shift 1]

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