Given the masses of various atomic particles {m}_{{p}}=1.0072 {u}, {m}_{{n}}=1.0087 {u} {m}_{{e}}=0.000548 {u}, {m}_{{{\ov v}}}=0, {m}_{{d}}=2.0141 {u} where {p} \equiv proton, {n} \equiv neutron, {e} \equiv electron, \overline{{v}} \equiv antineutrino and {d} \equiv deuteron. Which of the following process is allowed by momentum and energy conservation? [6 Sep 2020 Shift 2]

{n}+{n} \to deuterium atom (electron bound to the nucleus)

JEE Mains 06-Sep-2020 Shift 2 Solved Paper

Section: Physics

Question : 8 of 75

Marks: +1, -0

Given the masses of various atomic particles mp=1.0072u,mn=1.0087u me=0.000548u,mv=0,md=2.0141u where p≡ proton, n≡ neutron, e≡ electron, v≡ antineutrino and d≡ deuteron. Which of the following process is allowed by momentum and energy conservation?

[6 Sep 2020 Shift 2]

n+p→d+γ
e++e−→γ
n+n→ deuterium atom (electron bound to the nucleus)
p→n+e++v

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