A plane {\P} meets the coordinate axes at {\A}, {\B} and C respectively. The centroid of \\Delta {\ABC} is given to be (1,1,2) . Then the equation of the line through this centroid and perpendicular to the plane {\P} is : [6 Sep 2020 Shift 2]

Correct Answer is : x−12=y−12=z−21

\frac{x-1}{1}=\frac{y-1}{2}=\frac{z-2}{2}

\frac{x-1}{2}=\frac{y-1}{2}=\frac{z-2}{1}

\frac{x-1}{2}=\frac{y-1}{1}=\frac{z-2}{1}

\frac{x-1}{1}=\frac{y-1}{1}=\frac{z-2}{2}

JEE Mains 06-Sep-2020 Shift 2 Solved Paper

Section: Mathematics

Question : 56 of 75

Marks: +1, -0

A plane P meets the coordinate axes at A,B and C respectively. The centroid of Δ‌ABC is given to be (1,1,2). Then the equation of the line through this centroid and perpendicular to the plane P is :

[6 Sep 2020 Shift 2]

x−1
1
=
y−1
2
=
z−2
2
x−1
2
=
y−1
2
=
z−2
1
x−1
2
=
y−1
1
=
z−2
1
x−1
1
=
y−1
1
=
z−2
2

Validate

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