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Question : 17 of 75
Marks:
+1,
-0
Solution:
01=(√3+)m∕s 02= m1=2m2 After collision,
=(+√3)m∕s =? Applying conservation of linear momentum,
m101+m202=m11+m22 2m2(√3+)+0=2m2(+√3)+m22 v2=2(√3+)−2(+√3) =2(√3−)+2(−√3) 2=2(√3−1)(−) for angle between
1&2,
cos‌θ= =| 2(√3−1)(1−√3) |
| 2×2√2(√3−1) |
cos‌θ=⇒θ=105°or
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