When a particle of mass {m} is attached to a vertical spring of spring constant {k} and released, its motion is described by {y}({t})={y}_{0} \sin ^{2} \\omega{t}, where 'y' is measured from the lower end of unstretched spring. Then \\omega is : [6 Sep 2020 Shift 2]

JEE Mains 06-Sep-2020 Shift 2 Solved Paper

Section: Physics

Question : 13 of 75

Marks: +1, -0

When a particle of mass m is attached to a vertical spring of spring constant k and released, its motion is described by y(t)=y0sin2ωt, where 'y' is measured from the lower end of unstretched spring. Then ω is :

[6 Sep 2020 Shift 2]

√
g
y0
√
g
2y0
1
2
√
g
y0
√
2g
y0

Validate

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