If \\alpha and \\beta be two roots of the equation x^{2}-64 x+256=0 Then the value of ({\\alpha^{3}}/{\\beta^{5}})^{\frac{1}{8}}+({\\beta^{3}}/{\\alpha^{5}})^{\frac{1}{8}} is [6 Sep 2020 Shift 1]

JEE Mains 06-Sep-2020 Shift 1 Solved Paper

Section: Mathematics

Question : 68 of 75

Marks: +1, -0

If α and β be two roots of the equation x2−64x+256=0
Then the value of (

α3

β5

)

β3

α5

)

[6 Sep 2020 Shift 1]

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