Two different wires having lengths L_{1} and L_{2} , and respective temperature coefficient of linear expansion \\alpha_{1} and \\alpha_{2}, are joined end-to-end. Then the effective temperature coefficient of linear expansion is : [5 Sep 2020 Shift 2]

Correct Answer is : α1L1+α2L2L1+L2

4{\\alpha_{1} \\alpha_{2}}/{\\alpha_{1}+\\alpha_{2}} {{L}_{2} { L}_{1}}/{({ L}_{2}+{L}_{1} )^{2}}

2\sqrt{\\alpha_{1} \\alpha_{2}}

{\\alpha_{1} {L}_{1}+\\alpha_{2} {L}_{2}}/{{L}_{1}+{ L}_{2}}

JEE Mains 05-Sep-2020 Shift 2 Solved Paper

Section: Physics

Question : 14 of 75

Marks: +1, -0

Two different wires having lengths L1 and L2 , and respective temperature coefficient of linear expansion α1 and α2, are joined end-to-end. Then the effective temperature coefficient of linear expansion is :

[5 Sep 2020 Shift 2]

4
α1α2
α1+α2
L2L1
(L2+L1)2
2√α1α2
α1+α2
2
α1L1+α2L2
L1+L2

Validate

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