Three different processes that can occur in an ideal monoatomic gas are shown in the {P} vs {V} diagram. The paths are labelled as {A} \to{B}, {A}\to{C} and {A}\to{D} . The change ininternal energies during these process are taken as {E}_{ {AB}}, {E}_{ {AC}} and {E}_{ {AD}} and the workdone as {W}_{ {AB}}{W}_{ {AC}} and {W}_{ {AD}}. The correct relation between these parametersare : [5 Sep 2020 Shift 1]

Correct Answer is : EAB=EAC=EAD,WAB>0,WAC=0,WAD<0

E _{ AB }= E _{ AC } < E _{ AD }, W _{ AB } > 0, W _{ AC }=0, W _{ AD } < 0

E _{ AB } = E _{ AC } = E _{ AD }, W _{ AB } > 0, W _{ AC }=0, W _{ AD } < 0

E_{A B} < E_{A C} < E_{A D}, W_{A B} > 0, W_{A C} > W_{A D}

E_{A B} > E_{A C} > E_{A D}, W_{A B} < W_{A C} < W_{A D}

JEE Mains 05-Sep-2020 Shift 1 Solved Paper

Section: Physics

Question : 6 of 75

Marks: +1, -0

Three different processes that can occur in an ideal monoatomic gas are shown in the P vs V diagram. The paths are labelled as A→B,A→C and A→D. The change ininternal energies during these process are taken as EAB,EAC and EAD and the workdone as WABWAC and WAD.
The correct relation between these parametersare :

[5 Sep 2020 Shift 1]

EAB=EAC<EAD,WAB>0,WAC=0,WAD<0
EAB=EAC=EAD,WAB>0,WAC=0,WAD<0
EAB<EAC<EAD,WAB>0,WAC>WAD
EAB>EAC>EAD,WAB<WAC<WAD

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