If the function {f}( {x})=\{ \table k_1(x-\\pi)^2-1{,}, {x} \leq{ \\pi} ;k_2\cosx{,},x >\\pi is twice differentiable, then the ordered pair ({k}_{1},{ k}_{2} ) is equal to : [5 Sep 2020 Shift 1]

JEE Mains 05-Sep-2020 Shift 1 Solved Paper

Section: Mathematics

Question : 52 of 75

Marks: +1, -0

If the function f(x)={

k1(x−π)2−1,	x≤π
k2‌cosx‌,	x>π

is twice differentiable, then the ordered pair (k1,k2) is equal to :

[5 Sep 2020 Shift 1]

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2k1(x−π)−1	;	x≤π
−k2‌cosx	;	x>π

2k1	;	x≤π
−k2‌cos‌x	;	x>π