The function f(x) =\\begin{array}{c}{\\pi\end\frac{array}{4}+\tan ^{-1} x {,} ,{|x| }\\leq 1 ; {1} /{2}(|x|-1) {,} ,{|x|}>1 is : [4 Sep 2020 Shift 2]

Correct Answer is : continuous on R–{1} and differentiable on R – {–1, 1}.

continuous on R–{1} and differentiable on R – {–1, 1}.

both continuous and differentiable on R – {–1}.

continuous on R – {–1} and differentiable on R – {–1, 1}.

both continuous and differentiable on R –{1}

JEE Mains 04-Sep-2020 Shift 2 Solved Paper

Section: Mathematics

Question : 51 of 75

Marks: +1, -0

The function f(x)={

+tan−1x,

|x|≤1

(|x|−1),

|x|>1

is :

[4 Sep 2020 Shift 2]

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