On the x-axis and a dsitance x from the origin, the gravitational field due to a mass distribution is given by {{Ax}}/{({x}^{2}+ {a}^{2} )^{3 \/ 2}} in the {x} -direction. The magnitude of gravitational potential on the {x} -axis at a distance {x}, taking its value to be zero at infinity, is : [4 Sep 2020 Shift 1]

Correct Answer is : A(x2+a2)1∕2

{{A}}/{({x}^{2}+ {a}^{2} )^{1 \/ 2}}

{{A}}/{({x}^{2}+ {a}^{2} )^{3 \/ 2}}

{{A}} {({x}^{2}+ {a}^{2} )^{3 \/ 2}}

{{A}} {({x}^{2}+ {a}^{2} )^{1 \/ 2}}

JEE Mains 04-Sep-2020 Shift 1 Solved Paper

Section: Physics

Question : 6 of 75

Marks: +1, -0

On the x-axis and a dsitance x from the origin, the gravitational field due to a mass distribution is given by

(x2+a2)3∕2

in the x -direction. The magnitude of gravitational potential on the x -axis at a distance x, taking its value to be zero at infinity, is :

[4 Sep 2020 Shift 1]

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