A triangle {ABC} lying in the first quadrant has two vertices as {A}(1,2) and {B}(3,1) \\angle{BAC}=90^\circ, and {\ar}(\\Delta{ABC})=5 \\sqrt{5} sq. units, then the abscissa of the vertex C is: [4 Sep 2020 Shift 1]

JEE Mains 04-Sep-2020 Shift 1 Solved Paper

Section: Mathematics

Question : 55 of 75

Marks: +1, -0

A triangle ABC lying in the first quadrant has two vertices as A(1,2) and B(3,1) ∠BAC=90°, and ar(ΔABC)=5√5 sq. units, then the abscissa of the vertex C is:

[4 Sep 2020 Shift 1]

2+√5
1+√5
1+2√5
2√5−1

Validate

Go to Question:

Prev Question

Next Question