The specific heat of water =4200 {J} {kg}^{-1} {K}^{-1} and the latent heat of ice =3.4\times10^{5} {J} {kg}^{-1} 100 grams of ice at 0^\circ {C} is placed in 200 {g} of water at 25^\circ{C}. The amount of ice that will melt as the temperature of water reaches 0^\circ{C} is close to (in grams): [4 Sep 2020 Shift 1]

JEE Mains 04-Sep-2020 Shift 1 Solved Paper

Section: Physics

Question : 16 of 75

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The specific heat of water =4200Jkg−1K−1 and the latent heat of ice =3.4×105 J kg−1 100 grams of ice at 0°C is placed in 200 g of water at 25°C. The amount of ice that will melt as the temperature of water reaches 0°C is close to (in grams):

[4 Sep 2020 Shift 1]

61.7
63.8
69.3
64.6

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