JEE Mains 03-Sep-2020 Shift 2 Solved Paper

Section: Mathematics

© examsiri.com

Question : 66 of 75

Marks: +1, -0

If x3dy+xydx =x2dy+2ydx;y(2)=e and x>1, then y(4) is equal to :

[3 Sep 2020 Shift 2]

3
2
+√e
3
2
√e
1
2
+√e
√e
2

Go to Question:

Prev Question

Next Question