JEE Mains 03-Sep-2020 Shift 2 Solved Paper
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A block of mass 1.9 k g is at rest at the edge of a table, of height 1 m . A bullet of mass 0.1 k g collides with the block and sticks to it. If the velocity of the bullet is 20 m ∕ s in the horizontal direction just before the collision then the kinetic energy just before the combined system strikes the floor, is [Take g = 10 m ∕ s 2 . Assume there is no rotational motion and loss of energy after the collision is negligable.]
[3 Sep 2020 Shift 2]
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