JEE Mains 03-Sep-2020 Shift 1 Solved Paper

Section: Mathematics
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Question : 64 of 75
 
Marks: +1, -0
If Δ =|
x−22x−33x−4
2x−33x−44x−5
3x−55x−810x−17
|=
Ax3+Bx2+Cx+D, then B+C is equal to :
[3 Sep 2020 Shift 1]
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