Moment of inertia of a cylinder of mass M, length {L} and radius {R} about an axis passing through its centre and perpendicular to the axis of the cylinder is {I}= {M}({{R}^{2}}/{4}+{{L}^{2}}/{12} ). If such a cylinder is to be made for a given mass of material, the ratio L/R for it to have minimum possible I is :- [3 Sep 2020 Shift 1]

JEE Mains 03-Sep-2020 Shift 1 Solved Paper

Section: Physics

Question : 4 of 75

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Moment of inertia of a cylinder of mass M, length L and radius R about an axis passing through its centre and perpendicular to the axis of the cylinder is I= M(

). If such a cylinder is to be made for a given mass of material, the ratio L/R for it to have minimum possible I is :-

[3 Sep 2020 Shift 1]

√
2
3
3
2
√
3
2
2
3

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