Henry's constant (in kbar) for four gases \\alpha, \\beta\\gamma and \\delta in water at 298 {K} is given below: α β γ δ K_H 50 2 2\times10^{-5} 0.5 (density of water =10^{3} {kg} {m}^{-3} at 298 {K} ) This table implies that : [3 Sep 2020 Shift 1]

Correct Answer is : The pressure of a 55.5 molal solution of δ is 250 bar

The pressure of a 55.5 molal solution of \\gamma is 1 bar

The pressure of a 55.5 molal solution of \\delta is 250 bar

Solubility of \\gamma at 308 {K} is lower than at 298 {K}

\\alpha has the highest solubility in water at a given pressure

JEE Mains 03-Sep-2020 Shift 1 Solved Paper

Section: Chemistry

Question : 32 of 75

Marks: +1, -0

Henry's constant (in kbar) for four gases α,βγ and δ in water at 298 K is given below:

	α	β	γ	δ
KH	50	2	2×10−5	0.5

(density of water =103 kg m−3 at 298 K ) This table implies that :

[3 Sep 2020 Shift 1]

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