Let {f}:(-1, \infty) \to{R} be defined by {f}(0)=1 and{f}({x})= {1}/{ {x}} \log _{ {e}}(1+{x}), {x} \\neq0 . Then the function {f} [2 Sep 2020 Shift 2]

Correct Answer is : decreases in (−1,∞)

decreases in (-1,0) and increases in (0, \infty)

increases in (-1,0) and decreases in (0, \infty)

JEE Mains 02-Sep-2020 Shift 2 Solved Paper

Section: Mathematics

Question : 57 of 75

Marks: +1, -0

Let f:(−1,∞)→R be defined by f(0)=1 and f(x)=

loge(1+x),x≠0. Then the function f

[2 Sep 2020 Shift 2]

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