JEE Mains 02-Sep-2020 Shift 2 Solved Paper

Section: Physics

Question : 17 of 75

Marks: +1, -0

A 10µF capacitor is fully charged to a potential difference of 50 V. After removing the source voltage it is connected to an unchargedcapacitor in parallel. Now the potential difference across them becomes 20 V. Thecapacitance of the second capacitor is:

[2 Sep 2020 Shift 2]

10µF
15µF
20µF
30µF

Validate

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