A small block starts slipping down from a point {B} on an inclined plane {AB}, which is making an angle \\theta with the horizontal section {BC} is smooth and the remaining section CA is rough with a coefficient of friction \\mu . It is found that the block comes to rest as it reaches the bottom (point A) of the inclined plane. If {BC}=2 {AC} the coefficient of friction is given by \\mu= {k} \tan \\theta ). The value of {k} is _______. [2 Sep 2020 Shift 1]

JEE Mains 02-Sep-2020 Shift 1 Solved Paper

Section: Physics

Question : 23 of 75

Marks: +1, -0

A small block starts slipping down from a point B on an inclined plane AB, which is making an angle θ with the horizontal section BC is smooth and the remaining section CA is rough with a coefficient of friction µ. It is found that the block comes to rest as it reaches the bottom (point A) of the inclined plane. If BC=2 AC the coefficient of friction is given by µ= k‌tan‌θ ).
The value of k is _______.

[2 Sep 2020 Shift 1]

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