A charged particle (mass {m} and charge q )moves along {X} axis with velocity {V}_{0} . When itpasses through the origin it enters a regionhaving uniform electric field \overrightarrow{{E}}=- {E} \stackrel{\^}{{j}} whichextends upto {x}={d}. Equation of path of electronin the region x>d is : [2 Sep 2020 Shift 1]

Correct Answer is : y=qEdmV02(d2−x)

{y}={{qEd}}/{ {mV}_{0}^{2}}({{d}}/{2}- {x} )

{y}={{qEd}}/{ {mV}_{0}^{2}}(x-d )

{y}={{qEd^2}}/{ {mV}_{0}^{2}} x

JEE Mains 02-Sep-2020 Shift 1 Solved Paper

Section: Physics

Question : 17 of 75

Marks: +1, -0

A charged particle (mass m and charge q )moves along X axis with velocity V0. When itpasses through the origin it enters a regionhaving uniform electric field

→

=−E

whichextends upto x=d. Equation of path of electronin the region x>d is :

[2 Sep 2020 Shift 1]

y=
qEd
mV02
(
d
2
−x)
y=
qEd
mV02
(x−d)
y=
qEd
mV02
x
y=
qEd2
mV02
x

Validate

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