An electron with energy 0.1 {keV} moves at right angle to the earth's magnetic field of 1 \times 10^{-4} {Wbm}^{-} 2. The frequency of revolution of the electron will be (Take mass of electron =9.0 \times 10^{-31} {kg} ) [25-Jul-2022-Shift-2]

Magnetism and Matter

Section: Physics

Question : 29 of 73

Marks: +1, -0

An electron with energy 0.1keV moves at right angle to the earth's magnetic field of 1×10−4Wbm−
2. The frequency of revolution of the electron will be
(Take mass of electron =9.0×10−31kg )

[25-Jul-2022-Shift-2]

1.6×105Hz
5.6×105Hz
2.8×106Hz
1.8×106Hz

Validate

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