Two charges 7 \mu {\C} and -4 \mu {\C} are placed at (-7 {\cm}, 0,0) and (7 {\cm}, 0,0) respectively. Given, \epsilon_0=8.85 \times 10^{-12} {\C}^2 {\N}^{-1} {\m}^{-2}, the electrostatic potential energy of the charge configuration is: [23 Jan 2025 Shift 2]

Electrostatics Part 3

Section: Physics

Question : 49 of 70

Marks: +1, -0

Two charges 7µC and −4µC are placed at (−7‌cm,0,0) and (7‌cm,0,0) respectively. Given, ε0=8.85×10−12C2N−1m−2, the electrostatic potential energy of the charge configuration is:

[23 Jan 2025 Shift 2]

-1.5 J
-1.2 J
-2.0 J
-1.8 J

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