A particle of charge ' -q ' and mass ' m ' moves in a circle of radius ' r ' around an infinitely long line charge of linear density ' +\lambda '. Then time period will be given as: (Consider k as Coulomb's constant) [30-Jan-2024 Shift 2]

Correct Answer is : T=2πr√m2kλq

{\T}^2= {4 \pi^2 {\m}}/{2 {\k} \lambda {\q}} {\r}^3

T=2 \pi r \sqrt{\frac{m}{2 k \lambda q}}

{\T}=\frac{1}{2 \pi {\r}} \sqrt{ { {\m}/{2 {\k} \lambda {\q}}}

{\T}=\frac{1}{2 \pi} \sqrt{ {2 {\k} \lambda {\q}}/{ {\m}}}

Electrostatics Part 2

Section: Physics

Question : 6 of 100

Marks: +1, -0

A particle of charge ' −q ' and mass ' m ' moves in a circle of radius ' r ' around an infinitely long line charge of linear density ' +λ '. Then time period will be given as:
(Consider k as Coulomb's constant)

[30-Jan-2024 Shift 2]

T2=‌
4π2m
2kλq
r3
T=2πr√‌
m
2kλq
T=‌
1
2πr
√‌
m
2kλq
T=‌
1
2π
√‌
2kλq
m

Validate

Go to Question:

Prev Question

Next Question