Electrostatic Potential and Capacitance Part 1

According to given circuit diagram,
At t=0, the key is in closed position.
Current through the resistor will be maximum.
Using Ohm's law,
Imax=‌

V

R

⇒Imax=(‌

Q

C

)×‌

1

R

⇒‌‌Imax=(‌

30×10−6

3×10−6

)×‌

1

5×106

Imax=2×10−6A
Imax=2µA
The value of the current flowing through the 5Ω resistor is 2µA.
Hence, the value of the x to the nearest integer is 2 .