The magnetic field of an E.M. wave is given by \overrightarrow{B}= ( {\sqrt{3}}/{2} \stackrel{\^}{i}+\frac{1}{2} \stackrel{\^}{j}) 30 \sin [\omega (t-\frac{z}{c}) ] (S.I. Units). The corresponding electric field in S.I. units is [28 Jan 2025 Shift 2]

Correct Answer is : →E=(12^i−√32^j)30csin[ω(t−zc)]

\overrightarrow{E}= (\frac{3}{4} \stackrel{\^}{i}+\frac{1}{4} \stackrel{\^}{j}) 30 c \cos [\omega (t-\frac{z}{c}) ]

\overrightarrow{E}= (\frac{1}{2} \stackrel{\^}{i}+ {\sqrt{3}}/{2} \stackrel{\^}{j}) 30 c \sin [\omega (t+\frac{z}{c}) ]

\overrightarrow{E}= (\frac{1}{2} \stackrel{\^}{i}- {\sqrt{3}}/{2} \stackrel{\^}{j}) 30 c \sin [\omega (t-\frac{z}{c}) ]

\overrightarrow{E}= ( {\sqrt{3}}/{2} \stackrel{\^}{i}-\frac{1}{2} \stackrel{\^}{j}) 30 c \sin [\omega (t+\frac{z}{c}) ]

Electromagnetic Waves Part 2

Section: Physics

Question : 14 of 54

Marks: +1, -0

The magnetic field of an E.M. wave is given by

→

=(‌

√3

+‌

)30sin‌[ω(t−‌

)] (S.I. Units). The corresponding electric field in S.I. units is

[28 Jan 2025 Shift 2]

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