A plane electromagnetic wave is moving in free space with velocity c=3 \times 10^8 m \/ s and its electric field is given as \overrightarrow{E}=54 \sin (k z-\omega t) \hat{j} V \/ m, where \hat{j} is the unit vector along y-axis. The magnetic field vector \overrightarrow{B} of the wave is : [28 Jan 2026 Shift 2]

Correct Answer is : −1.8×10−7sin(kz−ωt)∧iT

-1.8 \times 10^{-7} \sin (k z-\omega t) \hat{i} T

+1.8 \times 10^{-7} \sin (k z-\omega t) \hat{i} T

1.4 \times 10^{-7} \sin (k z-\omega t) \hat{k} ⊤

1.4 \times 10^{-7} \sin (k z-\omega t) \hat{i} ⊤

Electromagnetic Waves Part 2

Section: Physics

Question : 1 of 54

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A plane electromagnetic wave is moving in free space with velocity c=3×108m∕s and its electric field is given as

→

=54sin‌(kz−ωt)

∧

V∕m, where

∧

is the unit vector along y-axis. The magnetic field vector

→

of the wave is :

[28 Jan 2026 Shift 2]

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