Magnetic field in a plane electromagnetic wave is given by B^{\to}=B_0\text{\sin}(kx+\omegat)j^{∧}T Expression for corresponding electric field will be : Where c is speed of light. [Main 8 April 2017]

Correct Answer is : →E=B0csin(kx+ωt)∧k V/m

E^{\to}=B_0c\text{\sin}(kx+\omegat)k^{∧} V/m

E^{\to}=B_0/c\text{\sin}(kx+\omegat)k^{∧} V/m

E^{\to}=-B_0c\text{\sin}(kx+\omegat)k^{∧} V/m

E^{\to}=B_0c\text{\sin}(kx-\omegat)k^{∧} V/m

Electromagnetic Waves Part 1

Section: Physics

Question : 88 of 100

Marks: +1, -0

Magnetic field in a plane electromagnetic wave is given by

→

=B0sin(kx+ωt)

∧

T Expression for corresponding electric field will be : Where c is speed of light.

[Main 8 April 2017]

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