Electromagnetic Induction Part 2
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Suppose a long solenoid of 100 cm length, radius 2 cm having 500 turns per unit length, carries a current I = 10 s i n ( ω t ) A , where ω = 1000 r a d . /s. A circular conducting loop ( B ) of radius 1 cm coaxially slided through the solenoid at a speed v = 1 c m ∕ s . The r.m.s. current through the loop when the coil B is inserted 10 cm inside the solenoid is
µ A . The value of α is _ _ _ _ 。
[Resistance of the loop= 10 Ω ]
[Resistance of the loop
[23 jan 2026 Shift 2]
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