If three helium nuclei combine to form a carbon nucleus then the energy released in this reaction is ______ \times 10^{-2} {\MeV}. (Given 1 {\u}=931 {\MeV} \/ {\c}^2, atomic mass of helium =4.002603 {\u}) [5 Apr 2024 Shift 1]

Atoms and Nuclei Part 3

Section: Physics

Question : 48 of 87

Marks: +1, -0

If three helium nuclei combine to form a carbon nucleus then the energy released in this reaction is ______ ×10−2‌MeV. (Given 1u=931‌MeV∕c2, atomic mass of helium =4.002603u)

[5 Apr 2024 Shift 1]

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