A star has 100 \% helium composition. It starts to convert three { }^4 {\He} into one { }^{12} {\C} via triple alpha process as { }^4 {\He}+{ }^4 {\He}+{ }^4 {\He} \rightarrow{ }^{12} {\C}+ {\Q}. The mass of the star is 2.0 \times 10^{32} {\kg} and it generates energy at the rate of 5.808 \times 10^{30} {\W}. The rate of converting these { }^4 {\He} to { }^{12} {\C} is {\n} \times 10^{42} { s}^{-1}, where {\n} is ______. [Take, mass of { }^4 {\He}=4.0026 {\u}, mass of { }^{12} {\C}=12 {\u} ] [9 Apr 2024 Shift 1]

Atoms and Nuclei Part 3

Section: Physics

Question : 38 of 87

Marks: +1, -0

A star has 100% helium composition. It starts to convert three ‌4‌He into one ‌12C via triple alpha process as ‌4‌He+‌4‌He+‌4‌He⟶‌12C+Q. The mass of the star is 2.0×1032‌kg and it generates energy at the rate of 5.808×1030W. The rate of converting these ‌4‌He to ‌12C is n×1042 s−1, where n is ______.
[Take, mass of ‌4‌He=4.0026u, mass of ‌12C=12u ]

[9 Apr 2024 Shift 1]

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