The minimum frequency of photon required to break a particle of mass 15.348 amu into 4 \alpha particles is \_\_\_\_ kHz . [mass of He nucleus = 4.002amu, 1amu = 1.66 × 10-27 kg, h=6.6 × 10-34 J. s and c=3 \times 10^8 m \/ s ] [22 Jan 2026 Shift 1]

Correct Answer is : 14.94×1019

Atoms and Nuclei Part 3

Section: Physics

Question : 11 of 87

Marks: +1, -0

The minimum frequency of photon required to break a particle of mass 15.348 amu into 4α particles is ____ kHz . [mass of He nucleus = 4.002amu, 1amu = 1.66 × 10-27 kg, h=6.6 × 10-34 J. s and c=3 ×108m∕s ]

[22 Jan 2026 Shift 1]

14.94×1020
9×1019
9×1020
14.94×1019

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