The mean free path of a molecule of diameter 5 \times 10^{-10} m at the temperature 41^{\circ} C and pressure 1.38 \times 10^5 Pa, is given as \_\_\_\_ m . (Given k_B=1.38 \times 10^{-23} J \/ K ). [28 Jan 2026 Shift 2]

Correct Answer is : 2√2×10−8

Thermodynamics Part 5

Section: Physics

Question : 2 of 69

Marks: +1, -0

The mean free path of a molecule of diameter 5×10−10m at the temperature 41∘C and pressure 1.38×105Pa, is given as ____ m . (Given kB=1.38×10−23J∕K ).

[28 Jan 2026 Shift 2]

2√2×10−10
10√2×10−8
2√2×10−8
2×10−8

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