Thermodynamics Part 3

Given, power consumed by refrigerator
P=35W=35Js−1
∴ Energy consumed by refrigerator per second, W=35J
Lower temperature limit, TL=−10°C=263K
Higher temperature limit, TH=25°C=298K
The coefficient of performance of refrigerator is given as
COP=

TL

TH−TL

=

Q

W

Here, Q is the heat transferred by the refrigerator.
Substituting the values, we get

263

298−263

=

Q

35

⇒Q=

263

35

×35=263J∕s
Thus, the average heat transfer by refrigerator per second is 263Js−1.