Following figure shows two process A and B for a gas. If \DeltaQ_Aand \DeltaQ_B are the amount of heat absorbed by the system in two cases, and \DeltaU _A and \DeltaU_B are changes in internal energies, respectively, then: [9 Apr 2019 Shift 1]

Correct Answer is : ΔQA>ΔQB,ΔUA=ΔUB

\\Delta Q_{A}>\\Delta Q_{B}, \\Delta U_{A}=\\Delta U_{B}

\\Delta Q_{A}<\\Delta Q_{B}, \\Delta U_{A}<\\Delta U_{B}

\\Delta Q_{A}>\\Delta Q_{B}, \\Delta U_{A}>\Delta U_{B}

\\Delta Q_{A}=\\Delta Q_{B}, \\Delta U_{A}=\\Delta U_{B}

Thermodynamics Part 2

Section: Physics

Question : 84 of 100

Marks: +1, -0

Following figure shows two process A and B for a gas. If ΔQAand ΔQB are the amount of heat absorbed by the system in two cases, and ΔUA and ΔUB are changes in internal energies, respectively, then:

[9 Apr 2019 Shift 1]

ΔQA>ΔQB,ΔUA=ΔUB
ΔQA<ΔQB,ΔUA<ΔUB
ΔQA>ΔQB,ΔUA>ΔUB
ΔQA=ΔQB,ΔUA=ΔUB

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