Rotational Motion Part 2

Angular momentum, L=Iω
The moment of inertia of the circular ring, I=Mr2
When masses are attached at diametrically opposite ends, the moment of inertia, I′=Mr2+2mr2
The new angular speed =ω′
So, the new angular momentum, L′=I′ω′
Using the law of conservation of angular momentum
Iω=I′ω′
⇒‌‌Mr2ω=(Mr2+2mr2)ω′
⇒‌‌ω′=‌

M

M+2m

ω