Let \overrightarrow{F} be the force acting on a particle having position vector \overrightarrow{r}, and \overrightarrow{\tau} be the torque of this force about the origin. Then [AIEEE 2003]

Correct Answer is : →r⋅→τ=0 and →F⋅→τ=0

\overrightarrow{r \cdot {\tau}^{\to}=0 and \overrightarrow{F} \cdot \overrightarrow{\tau} \neq 0

\overrightarrow{r} \cdot \overrightarrow{\tau} \neq 0 and \overrightarrow{F} \cdot \overrightarrow{\tau}=0

\overrightarrow{r} \cdot \overrightarrow{\tau} \neq 0 and \overrightarrow{F}, \overrightarrow{\tau} \neq 0

\overrightarrow{r} \cdot \overrightarrow{\tau}=0 and \overrightarrow{F} \cdot \overrightarrow{\tau}=0

Rotational Motion Part 1

Section: Physics

Question : 96 of 100

Marks: +1, -0

Let

→

be the force acting on a particle having position vector

→

, and

→

be the torque of this force about the origin. Then

[AIEEE 2003]

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