At a given point of time the value of displacement of a simple harmonic oscillator is given as y=A \cos (30^{\circ}). If amplitude is 40 {\cm} and kinetic energy at that time is 200 {\J}, the value of force constant is 1.0 \times 10^{ {\x}} {\Nm}^{-1}. The value of x is _______ [13-Apr-2023 shift 1]

Oscillations Part 2

Section: Physics

Question : 37 of 74

Marks: +1, -0

At a given point of time the value of displacement of a simple harmonic oscillator is given as y=A‌cos(30∘). If amplitude is 40‌cm and kinetic energy at that time is 200J, the value of force constant is 1.0×10xNm−1. The value of x is _______

[13-Apr-2023 shift 1]

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