A particle is subjected to two simple harmonic motions as: x_1=\sqrt{7} \sin 5 t {\cm} \text{ and } x_2=2 \sqrt{7} \sin (5 t+\frac{\pi}{3}) {\cm} where x is displacement and t is time in seconds. The maximum acceleration of the particle is x \times 10^{-2} {\ms}^{-2}. The value of x is : [2 Apr 2025 Shift 1]

Oscillations Part 2

Section: Physics

Question : 11 of 74

Marks: +1, -0

A particle is subjected to two simple harmonic motions as:
x1=√7sin‌5t‌cm‌ and ‌x2=2√7sin‌(5t+‌

)‌cm where x is displacement and t is time in seconds.
The maximum acceleration of the particle is x×10−2ms−2. The value of x is :

[2 Apr 2025 Shift 1]

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