Motion in a Straight Line

Given that initial speed of two cars u and 4u and final speed v is 0 for both car. Both car is gradually slowing down so acceleration =(−a)
So formula becomes, 0=u2−2a s.
⇒u2=2as
For first car u2=2as1.....(i)
For second car (4u)2=2as2 ....(ii)
Dividing (i) and (ii),
‌

u2

16u2

=‌

2as1

2as2

⇒‌

1

16

=‌

s1

s2