An object, moving with a speed of 6.25 {\m} \/ { s}, is decelerated at a rate given by : \frac{d v}{d t}=-2.5 \sqrt{v} where {\v} is the instantaneous speed. The time taken by the object, to come to rest, would be: [AIEEE 2011]

Motion in a Straight Line

Section: Physics

Question : 106 of 119

Marks: +1, -0

An object, moving with a speed of 6.25m∕ s, is decelerated at a rate given by : ‌

=−2.5√v where v is the instantaneous speed. The time taken by the object, to come to rest, would be:

[AIEEE 2011]

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