Motion in a Plane

Given, horizontal velocity of helicopter, ux=v
Height of the helicopter from ground = h
The given condition can be drawn in the figure given below Here, M is the position of man.
Let, time taken by food packet to reach ground from helicopter = t
Acceleration due to gravity, g=10ms−2
Initial velocity of food packet along Y-axis, uy=0
Since, h=uyt+

1

2

gt2
∴t=√

2h

g

and distance travelled by helicopter in time t along horizontal direction
⇒x=uxt
=v√

2h

g

Hence, distance of helicopter from man,
H=√h2+x2=√h2+(v√

2h

g

)2
=√h2+

v22h

g