The position vector of a moving body at any instant of time is given as \overrightarrow{r}= (5 t^2 \stackrel{\^}{i}-5 t \stackrel{\^}{j}) {\m}. The magnitude and direction of velocity at t=2 { s} is, [24 Jan 2025 Shift 2]

Correct Answer is : 5√17m∕ s, making an angle of tan−14 with -ve Y axis

5 \sqrt{17} {\m} \/ { s}, making an angle of \tan ^{-1} 4 with -ve Y axis

5 \sqrt{17} {\m} \/ { s}, making an angle of \tan ^{-1} 4 with +ve X axis

5 \sqrt{15} {\m} \/ { s}, making an angle of \tan ^{-1} 4 with + {\ve} X axis

5 \sqrt{15} {\m} \/ { s}, making an angle of \tan ^{-1} 4 with -ve Y axis

Motion in a Plane

Section: Physics

Question : 14 of 88

Marks: +1, -0

The position vector of a moving body at any instant of time is given as

→

=(5t2

−5t

)m. The magnitude and direction of velocity at t=2 s is,

[24 Jan 2025 Shift 2]

Go to Question:

Prev Question

Next Question