Laws of Motion Part 1

Let acceleration of ball =

→

a

b and acceleration of man is =

→

a

m
With respect to the man standing in the lift, the acceleration of the ball

→

a

bm=

→

a

b−

→

a

m
⇒abm=g−a
Where a is the acceleration of the man as the acceleration of the lift is a.
With respect to the man standing on the ground the acceleration of the ball

→

a

bm=

→

a

b−

→

a

m
⇒abm=g−0
=g