Laws of Motion Part 1
© examsiri.com
Question : 12 of 100
Marks:
+1,
-0
Two inclined planes are placed as shown in figure. A block is projected from the Point A of inclined plane A B along its surface with a velocity just sufficient to carry it to the top Point B at a height 10 m . After reaching the Point B the block slides down on inclined plane BC . Time it takes to reach to the point C from point A is t ( √ 2 + 1 ) s. The value of t is _______.
(useg = 10 m ∕ s 2 )
(use
[27-Jul-2022-Shift-2]
- Your Answer:
Go to Question: