The distance of centre of mass from end A of a one dimensional rod (A B) having mass density \rho=\rho_0(1-\frac{x^2}{L^2}) {\kg} \/ {\m} and length L (in meter) is \frac{3 L}{\alpha} {\m}. The value of \alpha is_____ (where {\x} is the distance from end {\A} ) [28-Jul-2022-Shift-2]

Centre of Mass and Collision Part 1

Section: Physics

Question : 6 of 100

Marks: +1, -0

The distance of centre of mass from end A of a one dimensional rod (AB) having mass density ρ=ρ0(1−‌

)‌kg∕m and length L (in meter) is ‌

m. The value of α is_____ (where x is the distance from end A )

[28-Jul-2022-Shift-2]

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