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Question : 25 of 72
Marks:
+1,
-0
Solution:
‌=++,‌‌=3+2−,‌‌=λ+µ‌×=×‌⇒(−)×=0‌⇒|(−)=(−2++2)‌⇒=‌−‌+‌Given
⋅=1‌‌+‌=1‌⇒−λ+2µ=3Also
is perpendicular to
‌⇒⋅=0‌⇒λ+µ=0‌⇒λ=−µPut in (i)
‌µ+2µ=3⇒3µ=3‌⇒µ=1⇒λ=−1‌∴|3λ+µ|2⇒9λ2||2+µ2||2+2⋅3⋅λ⋅µ⋅
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