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Vector Algebra Part 3

Section: Mathematics
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Question : 15 of 72
 
Marks: +1, -0
For a triangle ABC, let
→
p
=
→
BC
,
→
q
=
→
CA
 and
→
r
=
→
BA
. If |
→
p
|=2√3,|
→
q
|=2 and cos‌θ=‌
1
√3
, where θ is the angle between
→
p
 and
→
q
, then |
→
p
×(
→
q
−3
→
r
)|2+3|
→
r
|2 is equal to :
[21 Jan 2026 Shift 2]
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