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Question : 92 of 100
Marks:
+1,
-0
Solution:
||||||=14∧=∧=∧=θ=‌So,
⋅=−‌ab,⋅=−‌bc,⋅.=−‌‌ac(let)
(×)⋅(×)=(⋅)(⋅)−(⋅)(⋅)=‌ab2c+‌ab2c=‌ab2c Similarly
(×)⋅(×) =‌abc2 (×)⋅(×) =‌a2bc 168 =‌abc(a+b+c) So,
(a+b+c)=16
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